Determine the centripetal force upon a 40-kg child who makes 10 revolution around the cliffhanger in 29.3 seconds. the radius of the barrel is 2.90 meters

The centripetal force acting on the child is 39400.56 N.

Explanation:

Given:

Mass of the child is,

Radius of the barrel is,

Number of revolutions are,

Time taken for 10 revolutions is,

Therefore, the time period of the child is given as:

Now, angular velocity is related to time period as:

Now, centripetal force acting on the child is given as:

Therefore, the centripetal force acting on the child is 39400.56 N.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft