)find the potential away from the axis (i. e nonzero θ) , for distances r > r, by using the result above and fiddling with the legendre formula, griffiths’ boxed equation 3.65. you will in principle need an infinite sum of terms here - but for this problem, just work out explicitly what the first two non-zero terms are. (it might to remember that pl(1) is always equal to one, and you will have to think mathematically about how the formula above behaves for r > > r.) (b) look at your answer to part a, and compare i

Did the proton move into a region of higher potential or lower potential? did the proton move into a region of higher potential or lower potential? because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential.because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential.because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential.because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential.request answerpart bwhat was the potential difference that stopped the proton? express your answer with the appropriate units.î”v î” v = nothingnothingrequest answerpart cwhat was the initial kinetic energy of the proton, in electron volts? express your answer in electron volts.ki k i = nothing ev request answerprovide feedback

It can take some of those large , industrial vehicles up to feet to stop when traveling only 60 mph, and therefore , you shoukd be mindful to not be jn the traffic right in front of them a. 100 feet b. 200 feet c. 335 feet d. 425 feet

The slope of a velocity time graph over any interval of time gives the during that interval