Aparallel plate capacitor is made with a separation betweentheplates of 6.3×10−7m and the gap is filled with a dielectric with 휅=9.6. the capacitor is then connected to a battery with an emf of 400 v, andthe capacitorstores 120 j of energy in the electric field. what is the area of the capacitor plates? a.9.4×10-3m2b.9.0×10-2m2c.5.6×100m2 d.1.1×101m2e.1.1×102m2

D)

Explanation:

The capacitance of a parallel plate capacitor with a separation between the plates d, area of the plates A filled with a dielectric with relative permittivity k is given by the formula:

where is the permittivity of free space (vacuum).

The energy stored on a capacitor can be calculated with:

Combining these two equations we have:

Which for the area and our values is:

answer: good job it's all correct !

explanation: