Atransformer connected to a 120-v (rms) ac line is to supply 12,500 v (rms) for a neon sign. to reduce shock hazard, a fuse is to be introduced in the primary circuit; the fuse is to blow when the rms current in the secondary circuit exceeds 8.50 ma. (here the "primary" line is the 120 v line and the "secondary" is the 12,500 v line). part a
part a). what is the ratio of secondary to primary turns of the transformer? n2/n1 =
part b). what power must be supplied to the transformer when the rms secondary current is 8.50 ma? p=
part c) what current rating should the fuse in the primary circuit have? i1=

a) 104

b) 106

c) 884 mA

Explanation:

The ratio of the transformer is given by:

We need to know the current in the primary in order to obtain the power applied.

The current rating of the fuse is the current on the primary, 884mA as we calculated before in order to obtain the power.

this means that the temperature of both substances will be equal

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.