Around loop of wire carries a current of 100 a, has a radius of 10 cm, and its normal (vector) makes an angle of 30∘ with a magnetic field of 0.524 t. 1) what is the torque on the loop? (express your answer to two significant figures.)

0.823 Nm

Explanation:

current, i = 100 A

radius, r = 10 cm

Angle between the normal and the magnetic field, θ = 30°

Magnetic field, B = 0.524 T

Torque is defined as the

Torque = 0.823 Nm

Thus, the torque is 0.823 Nm.

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

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