Calculate the de brogile wavelength of an electron traveling at 2.0

answer:

explanation: before taking the qutetion we should know about what is de brogile equation and why we use it. we know that waves have characteristics of particals also particals have characteristics of waves for that de brogile equation is introduced

λ = h/ (mv)

λ = de brogile wave length

h - planks constant

m - mass

v - velocity

λ =6.62×10-34 / (9.31×10-31×2)

λ = 3.55×10-4 m

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y