Agolf ball reaches a height of 150 m before it stops rising and starts to fall to the ground. what is the golf balls speed (rounded to the nearest whole number) right before it hits the ground?

v = 54 m/s

Explanation:

Given,

The maximum height of the flight of golf ball, h = 150 m

The velocity at height h, u = 0

The velocity of the golf ball right before it hits the ground, v = ?

Using the III equations of motion

                                 v² = u² + 2gh

Substituting the given values in the above equation,

                                 v² = 0 + 2 x 9.8 x 150 m

                                     = 2940

                                  v = 54 m/s

Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s

conservation of mass

mass before something happens = mass afterwards