If two equal charges each of 1 c each are separated in air by a distance of 1 km, what is the magnitude of the force acting between them? you will see that even at a distance as large as 1 km, the repulsive force is substantial because 1 c is a very significant amount of charge.

9000 N

Explanation:

Charge, q1 = q2 = 1 C

Distance, r = 1 km = 1000 m

According to the coulomb's law, the force between the two charged particles is given by

By substituting the values

F = 9000 N

Thus, the force of repulsion between the charges is 9000 N.

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.