Two compressible solids are formed into spheres of the same size. the bulk modulus of sphere two is twice as large as the bulk modulus of sphere one. you now increase the pressure on both spheres by the same amount. as a result of the increased pressure, how is the change in volume of sphere two (δv2) related to the change in volume of sphere one (δv1)?

The variables for this experiment include mass, volume and the materials in the various balls, as well as their densities. in part iii, you will be investigating the questionable baseball. use the drop-down menus to complete the sentences and identify the independent and dependent variables. in part iii, the independent variable, the one that is intentionally manipulated, is . in part iii, the dependent variable, the one that you measure the response in, is

Laboratory experiments, observational field studies, and model-building are all examples of different forms of scientific investigations.  in what way do laboratory experiments primarily differ from other forms of scientific investigations?   a.  a laboratory experiment is the only accepted form of investigation within the scientific community.  b.  studies about how things behave in nature or studies involving very large objects are best answered through laboratory experiments.  c.  laboratory experiments involve the identification and control of variables.  d.  data can only be generated through laboratory experiments, not other forms of investigation.

Part f - example: finding two forces (part i) two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. the block in (figure 1) has a mass m=10kg and is being pulled by a force f on a table with coefficient of static friction îľs=0.3. four forces act on it: the applied force f (directed î¸=30â above the horizontal). the force of gravity fg=mg (directly down, where g=9.8m/s2). the normal force n (directly up). the force of static friction fs (directly left, opposing any potential motion). if we want to find the size of the force necessary to just barely overcome static friction (in which case fs=îľsn), we use the condition that the sum of the forces in both directions must be 0. using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: fcosî¸â’îľsn=0 fsinî¸+nâ’mg=0 in order to find the magnitude of force f, we have to solve a system of two equations with both f and the normal force n unknown. use the methods we have learned to find an expression for f in terms of m, g, î¸, and îľs (no n).