A50 g disk sits on a horizontally rotating turntable. the turntable makes exactly 2 revolutions each second. the disk is located 17 cm from the axis of rotation of the turntable. (a) what is the frictional force acting on the disk?

Frictional force, f = 1.34 N

Explanation:

It is given that,

Mass of the disk, m = 50 g = 0.05 kg

The angular speed of the turntable,

The radius of the disk, r = 17 cm = 0.17 m

(a) Let f is the frictional force acting on the disk. The frictional force acting on the disk in rotational motion is given by :

f = 1.34 N

So, the frictional force acting on the disk is 1.34 N. Hence, this is the required solution.

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