Asimple electric motor consists of a 220-turn coil, 4.4 cm in diameter, mounted between the poles of a magnet that produces a 96-mt field. part a when a 15-a current flows in the coil, what is the coil's magnetic dipole moment?

The coil's magnetic dipole moment in the electric motor is 5.02 Am².

The given parameters;

The magnetic dipole moment is calculated as follows;

where;

A is the area of the coil,

Thus, the coil's magnetic dipole moment in the electric motor is 5.02 Am².

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Explanation:

It is given that,

Number of turns in the coil, N = 220

Diameter of the coil, d = 4.4 cm

Radius of the coil, r = 2.2 cm = 0.022 m

Magnetic field produced by the poles of magnet,

Current flowing in the coil, I = 15 A

Let M is the coil's magnetic dipole moment. Its formula is given by :

So, the coil's magnetic dipole moment is . Hence, this is the required solution.

he kicked it 10 feet straight up into the air? i think this works.

higher potential

explanation:

because it is in a high speed so it must move into a of high potential