An elevator mass of 7700 kg falls from a height of 32 m after a sudden failure in the hoisting cable. the mass is stopped by a spring at the bottom of the shaft. determine the spring constant (in kn/m) necessary to bring the elevator and occupants to rest without exceeding an acceleration of 5 g's.

k=28.29 kN/m

Explanation:

Given

mass

height from which Elevator falls

Let x be the compression in the spring

thus From conservation of Energy Potential energy will convert in to Elastic Potential Energy of spring

----------1

also maximum acceleration is 5g

thus

here

Substitute x in equation 1

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