Hen a 0.20-kg block is suspended from a vertically hanging spring, it stretches the spring from its original length of 0.050 m to 0.060 m. the same block is attached to the same spring and placed on a horizontal, frictionless surface. the block is then pulled so that the spring stretches to a total length of 0.10 m. the block is released at time t= 0 and undergoes simple harmonic motion. page 24.what is the maximum acceleration ofthe block?

Answer

mass of the block = 0.2 Kg

it stretches the spring from its original length of 0.050 m to 0.060 m.

total length = 0.1 m

FOR , VERTICAL SYSTEM:

K Δx = mg ,    Δx = 0.01 m

k =196 N/m

f = 4.98 Hz

for horizontal system

k Δ x = ma

a = 49 m/s²

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explanation: