Suppose that an ion source in a mass spectrometer produces doubly ionized gold ions (au2+), each with a mass of 3.27 × 10-25 kg. the ions are accelerated from rest through a potential difference of 1.90 kv. then, a 0.540-t magnetic field causes the ions to follow a circular path. determine the radius of the path.

Radius of the path is  

Explanation:

It is given that gold is doubly ionized

Charge

Mass of the each ion =

So total mass m =

Potential difference V = 1.9 KV

Magnetic field B = 0.540 T

We know that

We have to find the radius of the path

We know that radius of the path is given by

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

what question you dont ask a question

explanation: