Suppose that the dipole moment associated with an iron atom of an iron bar is 2.8 × 10-23 j/t. assume that all the atoms in the bar, which is 5.8 cm long and has a cross-sectional area of 1.5 cm2, have their dipole moments aligned. (a) what is the dipole moment of the bar? (b) what torque must be exerted to hold this magnet perpendicular to an external field of 2.2 t? (the density of iron is 7.9 g/cm3 and its molar mass is 55.9 g/mol.)

To solve this exercise it is necessary to apply the equations related to the magnetic moment, that is, the amount of force that an image can exert on the electric currents and the torque that a magnetic field exerts on them.

The diple moment associated with an iron bar is given by,

Where,

Dipole momento associated with an Atom

N = Number of atoms

y previously given in the problem and its value is 2.8*10^{-23}J/T

The number of the atoms N, can be calculated as,

Where

Density

Molar Mass

A = Area

L = Length

Avogadro number

Then applying the equation about the dipole moment associated with an iron bar we have,

PART B) With the dipole moment we can now calculate the Torque in the system, which is

Note: The angle generated is perpendicular, so it takes 90 ° for the calculation made.

coil wire, increase current, put iron inside the coil

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.