The maximum speed of a 3.00-kg object in simple harmonic motion is 4.00 m/s. the maximum acceleration of the object is 5.00 m/s2. what is the period of simple harmonic motion?

0.800 s
5.03 s
0.417 s
3.75 s
1.25 s

Time period = 5.03 s

Explanation:

Given:

Maximum speed of object in SHM is, m/s

Maximum acceleration of object in SHM is, m/s².

Mass of object is 3.00 kg.

We know that for an object in SHM, the velocity is given as:

Where,

Therefore, ------- 1

Also, for an object in SHM, the acceleration is given as:

Where, ---- 2

Now, dividing equation 2 by 1, we get

Now, time period is given as:

Therefore, the time period of simple harmonic motion is 5.03 s.

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