What replacement value of l should an engineer analyzing the circuit choose such that the current leads the applied voltage by 30.0°?
all other values in the circuit stay the same. solve the following equation for the inductive reactance: xl = xc + r tan(ϕ) substitute expressions for inductive reactance and capacitive reactance into the following expression: ωl = 1 ωc + r tan(ϕ) solve for l: l = 1 ω 1 ωc + r tan(ϕ) substitute the given values: l = 1 377 rad/s 1 (377 rad/s)(4.00 10-6 f) + (450 ω) tan(−30.0°)