To calibrate your calorimeter cup, you first put 45 ml of cold water in the cup, and measure its temperature to be 24.7 °c. you then pour 47 ml of hot water, temperature = 46.1 °c, into the cup and measure the temperature every thirty seconds over a 10 minute period. you extrapolate this "cooling curve" back to the time of addition and find that the "final temperature" after mixing is 33.4 °c. what is the heat change of the cold water in joules? give your answer in standard notation. do not input units.

Answer : The heat change of the cold water in Joules is,

Explanation :

First we have to calculate the mass of cold water.

As we know that the density of water is 1 g/mL. The volume of cold water is 45 mL.

Now we have to calculate the heat change of cold water.

Formula used :

where,

Q = heat change of cold water = ?

m = mass of cold water = 45 g

c = specific heat of water =

= initial temperature of cold water =

= final temperature  =

Now put all the given value in the above formula, we get:

Therefore, the heat change of cold water is

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

statement #3 on andre"s list is false.