Alarge bell is hung from a wooden beam so it can swing back andforth with negligible friction. the center of mass of the bell is0.60 m below the pivot, the bell has mass 34.0 kg, and the momentof inertia of the bell about an axis at the pivot is 18.0 kgm2 . the clapper is a small, 1.8-kg mass attached to oneend of a slender rod that has length l and negligible mass. theother end of the rod is attached to the inside of the bell so itcan swing freely about the same axis as the bell. what should bethe length l of the clapper rod for the bell to ring silently, thatis, for the period of oscillation for the bell to equal that forthe clapper?

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

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