Acopper tube with mass 100g and 10cm long contains a current of 1a running through to the right. a magnetic field is turned on going forward ("into the board") with a strength of 1t. in grams, rounded to the nearest tenth, what will the scale read? (note: the scale will read whatever force it needs to use to balance the tube divided by g = 9.81 m/s^2)

Scale reading will be 0.098            

Explanation:

We have given mass of the copper tube m = 100 gram = 0.1 kg

Length of the copper tube L = 10 cm = 0.1 m

Magnetic field B = 1 T

Current flowing through copper tube i = 1 A

Acceleration due to gravity

Gravitational force on the copper tube = mg = 0.1 ×9.81 = 0.981 N

Magnetic force on the copper tube = iBL = 1×1×0.1 = 0.1 N

So balancing force F = 0.981-0.1 = 0.881

We have given that scale reading will be balancing force divided by g

So scale reading

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unlike poles attract