Aracquet ball with mass m = 0.256 kg is moving toward the wall at v = 11.8 m/s and at an angle of θ = 29° with respect to the horizontal. the ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. the ball is in contact with the wall for t = 0.066 s.1)what is the magnitude of the initial momentum of the racquet ball? kg-m/s2) what is the magnitude of the change in momentum of the racquet ball? kg-m/s3) what is the magnitude of the average force the wall exerts on the racquet ball? n4) ballhitswall2 now the racquet ball is moving straight toward the wall at a velocity of vi = 11.8 m/s. the ball makes an inelastic collision with the solid wall and leaves the wall in the opposite direction at vf = -7.8 m/s. the ball exerts the same average force on the ball as before. what is the magnitude of the change in momentum of the racquet ball? kg-m/s5) what is the time the ball is in contact with the wall? s6). what is the change in kinetic energy of the racquet ball? j

Part a)

Part b)

Part c)

Part d)

Part e)

Part f)

Explanation:

As we know that initial velocity of the ball is given as

Now final velocity of the system is given as

Part a)

now magnitude of initial momentum is given as

Part b)

Change in momentum is given as

Part c)

As we know that average force is defined as the rate of change in momentum

so here we have

Part d)

Magnitude of change in momentum is given as

Part e)

As we know that in 2nd case the force is same as the initial force

so we will have

Part f)

Since this is elastic collision so change in kinetic energy must be ZERO

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