A50-g chunk of 80 degrees c iron is dropped into a cavity in a very large block of ice at 0 degrees c. show that 5.5 g of ice will melt. (the specific heat capacity of iron is 0.11 cal / (g * degree

5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

Explanation:

The concept to solve this problem is given by Energy Transferred, the equation is given by,

Where,

Q= Energy transferred

m = mass of water

c = specific heat capacity

Temperature change (K or °C)

Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,

Then we can calculate the heat absorbed by m grams of ice at 0°C, then

How Q_1=Q_2, so

Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

answer; equivalent to a one(1) horsepower motor;