2. derive an expression for the final velocity of an object dropped from some height (h)
above the ground, initially at rest, the instant before hits the ground. your equation
should be in terms of (h) and (g) only

v = √(2gh)

Explanation:

Given:

Δy = h

v₀ = 0

a = g

Find: v

v² = v₀² + 2aΔy

v² = (0)² + 2gh

v = √(2gh)

You can also prove this with conservation of energy.

PE = KE

mgh = ½mv²

v = √(2gh)

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answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .