In a physics lab, asha is given a 10.5 kg uniform rectangular plate with edge lengths 66.3cm by 52.1cm . her lab instructor requires her to rotate the plate about an axis perpendicular to its plane and passing through one of its corners, and then prepare a report on the project. for her report, asha needs the plate's moment of inertia with respect to given rotation axis. calculate .

The plate's moment of inertia is 2.489 kg * m²

Explanation:

Step 1: Data given

mass of the uniform rectangular plate = 10.5 kg

lengths of the plate = 66.3cm by 52.1cm

Step 2: Calculate moment of inertia

For an axis through the center of the rectangle, I = m[(w²+L²)/12

Using the parallel axis theorem, the added value of I = mR² = m[(w²/4 + L²/4]

IF we get both reactions together we get:

I = (m/3)*(w²+L²)

I = 10.5/3 *(0.663² + 0.521²)

I = 2.489 kg * m²

The plate's moment of inertia is 2.489 kg * m²

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day