Aneutron (mass 1.01 u) strikes a deuteron (mass 2.01 u), and they combine to form a tritium nucleus (mass 3.02 u). the neutron's initial velocity was 23.5i^+14.4j^mm/s and the tritium nucleus leaves the reaction with velocity 15.1i^+22.6j^mm/s. select the correct deuteron's velocity. express your answer in terms of i^ and j^. use the 'unit vector' button to denote unit vectors in your answer.

We have that for the Question, it can be said that the correct deuteron's velocity is

From the question we are told

A neutron (mass 1.01 u) strikes a deuteron (mass 2.01 u), and they combine to form a tritium nucleus (mass 3.02 u). The neutron's initial velocity was 23.5i^+14.4j^Mm/s and the tritium nucleus leaves the reaction with velocity 15.1i^+22.6j^Mm/s.

Select the correct d euteron's velocity. Express your answer in terms of i^ and j^. Use the 'unit vector' button to denote unit vectors in your answer.

Generally the equation for the momentum law   is mathematically given as

initial=final of the system

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= 10.88 10⁶ m/s

,   =  27.11 10⁶ m/s

Explanation:

This exercise should be solved using the concepts of momentum, as the cores are combined the shock is inelastic.  

Let us form a system constituted by the neutron, deuteron and tritium for this system all the forces during the crash are internal so that the moment is conserved. Let us remember that the moment is a vector quantity, so each component must be kept independent of the others.  

We establish a nomenclature  

Neutron  

mₙ = 1.1 u  

vₙ₀ = (235 i ^ 14.4 j ^) 10⁶ m/ s  

= 2.01 u

X axis  

p₀ₓ = mₙ vₙ₀ₓ +  

=  

Axis y  

= mₙ +  

=  

Let's write the conservation equations of the moment and solve  

p₀ₓ =

mₙn vₙ₀ₓ + = vTfx  

= - mₙ vₙ₀ₓ  

=  

mₙ + =  

= - mₙ = 3.02u 15.1 - 1.01u 23.5  

2.01 = 21.867  

= 21.867 / 2.01  

= 10.88 10⁶ m / s  

2.01u = 3.02u 22.6 - 1.01 14.4  

= 54.71 10⁶ /2.01

= 27.11 10⁶ m/s

260 miles per hour

explanation:

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)