#19 a 2100 kg truck travel north at 41 km/h turns east and accelerates to 51 km/h.
(a) what is the change in the truck’s kinetic energy? what are the
(b) magnitude
(c) direction of the change in its momentum?

Answer

given,

mass of truck = 2100 Kg

velocity in  north  direction = 41 km/h

                     = 41 x 0.278 m/s

                     = 11.398 m/s

velocity in  north  direction = 51 km/h

                     = 51 x 0.278 m/s

                     = 14.178 m/s

a) Change in K.E

          =

          =

          = 7.453 x 10⁴ J

b) Change in momentum

c) Direction of momentum

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