An alternating source drives a series rlc circuit with an emf amplitude of 6.04 v, at a phase angle of +30.3°. when the potential difference across the capacitor reaches its maximum positive value of +5.32 v, what is the potential difference across the inductor (sign included)?

-8.56V

Explanation:

Our values are given by,

e = 6.04 V

Φ = 30.3

VC = 5.32

We can calculate the voltage across the circuit with the emf formula, that is,

Now, Using Kirchoff Voltage Law,

Finally we have the potential difference across the inductor.

i think the answer would be b

reserve is the answer