Arectangular loop with dimensions 4.20 cm by 9.50 cm carries current i. the current in the loop produces a magnetic field at the center of the loop that has magnitude 3.10×10−5 t and direction away from you as you view the plane of the loop. part a what is the magnitude of the current in the loop?

I=1.48 A

Explanation:

Given that

B=3.1 x 10⁻5 T

b= 4.2 cm

l= 9.5 cm

The relationship for magnetic field  and current given as

Where

By putting the values

D=26.03 m⁻¹

I=1.48 A

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west