Find the total change in the internal energy of a gas that is subjected to the following two-step process. in the first step the gas is made to go through isochoric heating until 5560 j of heat is transferred into the gas and its pressure is 3.32 ✕ 105 pa. in the second step it is subjected to isobaric compression until its volume decreases by 7.30 ✕ 10−3 m3 and 1270 j of heat is transferred out of the gas. what is the total change in internal energy of this gas

U = 9253.6 J

Explanation:

It is given that,

Heat transferred in isochoric process,

Pressure in this process,

In the second step,

It is subjected to isobaric compression until its volume decreases by, (it decreases)

Heat transferred out of the gas,

In isochoric process, work done by the gas is zero as in this type volume is constant,

According to first law of thermodynamics,

.............(1)

In isochoric compression,

Let U is the total change in the internal energy of this gas. So,

U = 9253.6 J

So, the total change in the internal energy of this gas is $$9253.6 J. Hence, this is the required solution.

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.