Physics, 07.11.2019 01:31 chrischris1

A60,000 lb f-14 jet is conducting air maneuvers. in one, the pilot flies in a large vertical circle. at the bottom of the circle, while the jet is travelling at 400 m/s, the pilot experiences an acceleration of 4 g.
(a) what is the radius of the circle?
(b) what is the centripetal force?
(c) how great is the force of lift on the wings there?

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Answer from: kimberlyvazquez1121

a) The radius of the circle is 4078.719 meters.

b) The centripetal force is 1066217.04 newtons.

c) The force of lift on the wings there is 1332771.3 newtons.

a) Let suppose that the F-14 jet is experimenting a uniform circular motion, the centripetal acceleration (), in meters per square second, by the jet is described by the following expression:

$a = \frac{v^{2}}{R}$ (1)

Where:

- Speed of the aircraft, in meters per second.

- Radius of the circle, in meters.

If we know that $a = 4\cdot g$ , $g = 9.807\,\frac{m}{s^{2}}$ and $v = 400\,\frac{m}{s}$ , then the radius of the circle is:

$R = \frac{v^{2}}{a}$

$R = \frac{v^{2}}{4\cdot g}$

$R = \frac{\left(400\,\frac{m}{s} \right)^{2}}{4\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$R = 4078.719\,m$

The radius of the circle is 4078.719 meters.

b) The centripetal force (), in newtons, of the aircraft is equal to the product of the F-14 mass (), in kilograms, and the acceleration (), that is to say:

$F = m\cdot a$ (2)

If we know that $m = 27180\,kg$ ( $60000\,lb$ ), $a = 4\cdot g$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the centripetal force is:

$F = (27180\,kg)\cdot 4\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F = 1066217.04\,N$

The centripetal force is 1066217.04 newtons.

c) At the bottom of the circle, the lift force (), in newtons, is the sum of the weight of the aircraft (), in newtons, and the centripetal force (). By the Newton's Laws of motion, we get the following expression:

L = F + W (3)

If we know that $F = 1066217.04\,N$ , $W = m\cdot g$ , $m = 27180\,kg \,(60000\,lb)$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the lift force on the wings is:

$L = 1066217.04\,N + (27180\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$L = 1332771.3\,N$

The force of lift on the wings there is 1332771.3 newtons.

We kindly invite to check this question on centripetal forces: link

Answer from: Quest

2. they have negligible mass.

Answer from: Quest

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol

b. a hockey puck sliding across the ice

c. a compressed spring

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice is the correct option.

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A60,000 lb f-14 jet is conducting air maneuvers. in one, the pilot flies in a large vertical circle....

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