Two long parallel wires separated by 5.0 mm each carry a current of 60 a. these two currents are oppositely directed. what is the magnitude of the magnetic field at a point that is between the two wires and 2.0 mm from one of the two wires?

B = 0.002 T

Explanation:

It is given that,

Distance between two parallel wires, d = 5 mm = 0.005

Current in each wire, I = 60 A

Let B is the magnitude of the magnetic field at a point that is between the two wires and 2.0 mm from one of the two wires. Firstly, calculating the magnetic field due to first wire is given by :

The magnetic field due to second wire is given by :

Let B is the net magnetic field from wire A, so,

B = 0.002 T

Hence, this is the required solution.

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.