Two equal charges are separated by 3.7 x 10^-10 m. the force between the charges has a magnitude of 2.37 x 10^-3 n. what is the magnitude of q on the charges?

q= 1.9*10⁻¹⁶ C

Explanation:

To solve this problem we apply Coulomb's law:

Two point charges (q1, q2) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:

F=K*q₁*q₂/d² Formula (1)  

F: Electric force in Newtons (N)

K : Coulomb constant in N*m²/C²

q₁,q₂:Charges in Coulombs (C)  

d: distance between the charges in meters(m)

Data

F=2.37*10⁻³ N

K=8.99*10⁹N*m²/C²

q₁ = q₂=q

d= 3.7*10⁻¹⁰ m

Problem development

We replace data in the formula (1) to calculate q:

F=K*q₁*q₂/d²

F= K*q*q*/d²

F*d²= K*q²

F*d²/K= q²

q= 1.9*10⁻¹⁶ C

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.