The mine car and its contents have a total mass of 5.5 mg and a center of gravity at g. if the coefficient of static friction between the wheels and the tracks is μs = 0.4 when the wheels are locked, find the normal force acting on the front wheels at b and the rear wheels at a when the brakes at both a and b are locked. does the car move?

Don't smoke.it ruins your life.confront your husband on how you are feeling and why you're depressed.weed is never the answer.there are so many more options out there for depression.weed will make the depression worse.so, stay clean and you will have support

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)