Two cars of the same mass collide at an intersection. just before the collision one car is traveling east at 50.0 km/h and the other car is traveling south at 60.0 km/h. if the collision is completely inelastic, so the two cars move as one object after the collision, what is the speed of the cars immediately after the collision? km/h

v=39.051 m/s

Explanation:

Given

Two cars having same mass, let say m

One is traveling east 50 km/h and one is traveling 60 km/h south

after collision they stick together and move with common velocity v at angle of

conserving Momentum in east i.e horizontal direction

---1

conserving momentum in south direction i.e. in vertical direction

---2

Divide 1 &2  we get

w.r.t east clockwise

Put value of is equation 1

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

the answer to this is proletariats.

hope this : )