Amine car (mass mcar = 450 kg) rolls at a speed of vcar = 0.55 m/s on a horizontal track, as the drawing shows. an mcoal = 140 kg chunk of coal has a speed of vcoal = 0.73 m/s when it leaves the chute. determine the speed of the car-coal system after the coal has come to rest in the car. (assume the angle α = 26°.)

The speed of the car-coal system after the coal has come to rest in the car is 0.37 m/s.

Explanation:

Given that,

Mass of car = 450 kg

Velocity of car = 0.55 m/s

Mass of coal = 140 kg

Velocity of coal = 0.73 m/s

Suppose the angle is horizontal angle .

We need to calculate the speed of the car-coal system after the coal has come to rest in the car

Using conservation of momentum

Put the value into the formula

Hence, The speed of the car-coal system after the coal has come to rest in the car is 0.37 m/s.

explanation:

newton's third law, for every action there is an equal and opposite reaction.

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