Askater of mass 40 kg is carrying a box of mass 5 kg. the skater has a speed of 5 m/s with respect to the floor and is gliding without any friction on a smooth surface. a. find the momentum of the box with respect to the floor. b. find the momentum of the box with respect to the floor after she puts the box down on the frictionless skating surface.

For the part a) we need only the momentum of the box and we have the data to find it.

Momentum is given by,

where clearly, p is the momentum, m the mass of the box and v is the velocity.

Substituting,

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

It is the same that part a)

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s