An electric pump rated 1.5 kw lifts 200kg of water through a vertical height of 6m in 10 secs: way is the efficiency of the pump?

80%

Explanation:

Efficiency = Power output / Power input × 100 %

To calculate efficiency we need to find power output of electric pump.

We can use,

Work done = Energy change

Work done per second = Energy change per second

Work done per second = Power

Therefore, Power = Energy change per second

                              = Change in potential energy of water per second

                              =mgh / t

                              = 200× 10×6 / 10

                              = 1200 W = 1.2 kW

Now use the first equation to find efficiency,

Efficiency = × 100%

                = 80 %

its a 5.5 n

glad that

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