Agroup of students perform the same "conservation of mechanical energy" experiment that you performed in lab by allowing a solid sphere and then a solid cylinder to roll down the ramp. both objects were released from the same position at the top of the ramp. if the speed vsphere of the solid sphere at the bottom of the ramp was 1.25 m/s, what would be the speed vcylinder at the bottom of the ramp?

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.