An ice rescue team pulls a stranded hiker off a frozen lake by throwing him a rope and pulling him horizontally across the essentially frictionless ice with a constant force. the hiker weighs 1040 n, and accelerates across the ice at 1.10 m/s2. what is the magnitude of the tension in the rope? (ignore the mass of the rope.)

T=116.84 N

Explanation:

Given

Weight of hiker =1040 N

acceleration

Force exerted by Rope is equal to Tension in the rope

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s