Asquare loop of wire surrounds a solenoid. the side of the square is 0.1 m, while the radius of the solenoid is 0.025 m. the square loop has a resistance of 30 w. the solenoid has 500 turns and is 0.3 m long. the current in the solenoid is increasing at a constant rate of 0.7 a/s. what is the current flowing in the square loop?

Explanation:

We first calculate the change in magnetic flux () due to the change in the magnitude of magnetic field (B), since que current (I) in the solenoid changes. B and are given by:

In this case, the magnetic field is always perpendicular to the square loop. We replace (2) in (1):

According to Faraday's law:

The minus sign means that the resulting current will have a direction such that the induced magnetic field will oppose the original change in flux. Here, n is the number of turns per unit length and A is the solenoid area

Recall that is an induced voltage. We use the Ohm's law to calculate the current:

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