The heating element of a coffeemaker operates at 120 v and carries a current of 2.00 a. assuming that the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.500 kg of water from room temperature (23.0°c) to the boiling point. (the specific heat of water is c= 4186 j/kg oc. the energy required to bring the water to the boiling point is q = m c δt.)

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Explanation:

The heat needed will be provided by the power dissipated by the resistor. This power gives certain energy per unit time, so we multiply it by time to get the energy provided: .

The equation of heat given mass, specific heat and temperature change is , and the equation of power dissipated by a resistor is .

Putting all together:

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Which means:

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From 23.0°C to 100°C we have a , which we won't need to put in Kelvin in this case since it is a variation, so for our values we have:

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the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.