Aproton moves at constant velocity in the direction, through a region in which there is an electric field and a magnetic field. the electric field is in the direction, and has magnitude 800 v/m. the magnetic field is in the direction, and has magnitude 0.25 t. collapse question part part 1 incorrect answer. your answer is incorrect. try again. what is the magnitude of the net force on the proton?

Explanation:

It is given that, a proton moves at constant velocity, through a region in which there is an electric field and a magnetic field such that,

The electric field is, E = 800 V/m

Magnetic field, B = 0.25 T

We know that the net force in the region of magnetic and electric field is given by Lorentz forces. But here, the proton moves with constant velocity. So, the net force acting on it is 0.

i.e.

Hence, this is the required solution.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6