The emission line used for zinc determinations in atomic emission spectroscopy is 214 nm. if there are 9.00×1010 atoms of zinc emitting light in the instrument flame per second, what energy (in joules) must the flame supply during this time to achieve this level of emission?

Explanation:

The energy emitted by a single photon is given by:

where

h is the Planck constant

c is the speed of light

is the wavelength of the photon

For the photons emitted by the zinc atoms,

So the energy of a single photon emitted is

And since the number of atoms is

The total energy emitted will be

cant without the picture! ?