Apoint charge with a charge q1 = 3.60 μc is held stationary at the origin. a second point charge with a charge q2 = -4.60 μc moves from the point x= 0.100 m , y= 0 to the point x= 0.250 m , y= 0.250 m .how much work w is done by the electric force on the moving point charge?

W = -1.069 J

Explanation:

To find the work (W) of the electric force, we can use the formula:

W = q.k₀.Q(1/r₁ - 1/r₂)

q = moving point charge

k₀ = 9.10⁹ Nm²/C²

Q = stationary charge

r₁ = distance from origin to starting point

r₂ = distance from origin to ending point

r₁ = 0.100 - 0 = 0.1

r₂ = √((0.25-0)² + (0.25-0)²) = √(0.25² + 0.25²) = √0.125 = 0.3536

W = -4.6*10⁻⁶*9*10⁹*3.6*10⁻⁶(1/0.1 - 1/0.3536)

W = -149.04*10⁻³(10 - 2.8284)

W = -149.04*10⁻³*7.1716 = -1068.85*10⁻³ = -1.069 J

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.