Calcular la relación de longitudes que deben cumplir dos varillas cuyos coeficientes de dilatación sonde 0.97 / gradocentigrado para que a cualquier temperatura la diferencia sea de 5cm

r = 1

Explanation:

Si

ΔL₁ = ΔL₂ = 5 cm = 0.05 m

sabiendo que

ΔL = α*ΔT

en ambas varillas los coeficientes de dilatación son los mismos, es decir:

α₁ = α₂ = α = 0.000097 / ºC

luego suponemos que la variación de temperatura es la misma para ambas varillas

ΔT₁ = ΔT₂ = ΔT

igualando ΔL resulta:

ΔL₁ = ΔL₂   ⇒   α₁*ΔT₁ = α₂*ΔT₂ = α*ΔT

La relación de longitudes se plantea como sigue:

r = ΔL₂ / ΔL₁ = α*ΔT / α*ΔT = 1

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

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