Askater starts skating from rest and speeds up to 6m/s^2 in 12 seconds. what is the acceleration of the skater?

Explanation:

The acceleration of an object is given by the equation

where

v is the final velocity of the object

u is the initial velocity

t is the time taken for the velocity to change from u to v

For the skater in this problem we have:

u = 0 (assuming it starts from rest)

v = 6 m/s is the final velocity of the skater

t = 12 s is the time taken

Substituting, we find

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.