An athlete whirls a 6.55 kg hammer tied to the end of a 1.3 m chain in a simple horizontal circle where you should ignore any vertical deviations. the hammer moves at the rate of 1.4 rev/s. what is the centripetal acceleration of the hammer? assume his arm length is included in the length given for the chain. answer in units of m/s 2 .

Centripetal Acceleration = 100.59 m/s²

Explanation:

Given that,

Mass of the hammer, m = 6.55 Kg

Length of chain including arm length, r = 1.3 m

The angular velocity of hammer, ω = 1.4 rev/s

                                                           = 8.79646 rad/s  (1 rev = 6.28 rad)

The centripetal acceleration is given by the relation,

                                  a = V²/ r

where V is tangential velocity of the hammer

Since,

                                  V  =  r ω

Therefore,

                                   a  =  rω²

Substituting the given values in the above equation,

                                  a  = 1.3 x 8.79646²

                                  a  = 100.59  m/s²

Thus, the centripetal acceleration of the hammer is 100.59  m/s².

1/0.14nm = 10^10/1.4 a lot

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