Asystem of inertia 0.47 kg consists of a spring gun attached to a cart and a projectile. the system is at rest on a horizontal low-friction track. a 0.050-kg projectile is loaded into the gun, then launched at an angle of 40∘ with respect to the horizontal plane.

with what speed does the cart recoil if the projectile rises 2.3 m at its maximum height?

0.95 m/s

Explanation:

Find the vertical component of the projectile's initial velocity.

Given:

Δy = 2.3 m

v = 0 m/s

a = -9.8 m/s²

Find: v₀

v² = v₀² + 2aΔy

(0 m/s)² = v₀² + 2 (-9.8 m/s²) (2.3 m)

v₀ = 6.71 m/s

Find the horizontal component of the projectile's initial velocity using trigonometry.

tan 40° = 6.71 m/s / v

v = 8.00 m/s

Momentum is conserved:

(0.47 kg) (0 m/s) = (0.050 kg) (8.00 m/s) + (0.47 kg − 0.050 kg) v

v = -0.95 m/s

The cart recoils at 0.95 m/s.

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!