Ashopper walks eastward 5.4 meters and then westward 8.9

meters.

student name:

abdinasir gaal

level:

apprentice

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for this motion, what is the distance moved?

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1

#2

#3

distance =

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what is the magnitude and direction of the displacement?

magnitude =

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We know that he first walks 5.4 meters to east, and then a distance of 8.9 to the west.

If we define the positive x-axis as the east, then the negative x-axis is the west. and the distances walked can be:

first 5.4m and then -8.9m

The distance moved:

This is the total distance moved, in this case, he first moves a distance of 5.4 meters and then a distance of 8.9 meters, the total distance is: 5.4m + 8.9 m = 14.3m

now the displacement is the diference in the initial position and the final position.

if the initial position is the zero at the x-axis, the final position is

p = 5.4m - 8.9m = -3.5m

This means that the magnitude is 3.5 meters, and the direction is the negative x-axis (or west in this case)