Aperson is pulling their 20 kg luggage using the luggage handle. the handle is at an angle of 56 degrees above the horizontal. if the person is pulling with a force of 71 n, what is the horizontal acceleration of the luggage (ignore all friction)
3.19 m/s^2
1.99 m/s^2
0.74 m/s^2
1.02 m/s^2

The answer to your question is:  a = 1.99 m/s²

Explanation:

Data

mass = 20 kg

angle = 56°

Force = 71 N

horizontal acceleration = ?

Process

Find the horizontal force

                                           cos Ф = adjacent side / hypotenuse

                                          adjacent side = hypotenuse x cosФ

                                          adjacent side = 71 x cos 56

                                          a.s. = 39.70 N

Newton's second law

                                  F = ma

                                  a = F/m

                                 a = 39.7 / 20

                                  a = 1.99 m/s²

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation: